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javascript - jquery : wait until all ajax calls finish then continue - Stack Overflow
I do not like any answer at all, the best way (since Jquery 1.5+) is to use Deferred objects, those are objects to manipulate async calls, you can solve :
$.when($.ajax("/page1.php"), $.ajax("/page2.php"))
.then(myFunc, myFailure);
This way myFunc executes after the 2 ajax calls are made, and myFailure if either one has an error.
You can read more about it in the jquery official documentation: (Link->http://ift.tt/1pSQ1uT)
http://ift.tt/1idrgly
http://ift.tt/1idrfOt
I do not like any answer at all, the best way (since Jquery 1.5+) is to use Deferred objects, those are objects to manipulate async calls, you can solve :
$.when($.ajax("/page1.php"), $.ajax("/page2.php"))
.then(myFunc, myFailure);
This way myFunc executes after the 2 ajax calls are made, and myFailure if either one has an error.
You can read more about it in the jquery official documentation: (Link->http://ift.tt/1pSQ1uT)
http://ift.tt/1idrgly
http://ift.tt/1idrfOt
from Public RSS-Feed of Jeffery yuan. Created with the PIXELMECHANICS 'GPlusRSS-Webtool' at http://gplusrss.com http://ift.tt/1pSQ1Lq
via LifeLong Community
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