[ACM] POJ 3061 Subsequence (尺取法) - 逆风的方向 更适合飞翔 - 博客频道 - CSDN.NET Description A sequence of N positive...

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[ACM] POJ 3061 Subsequence (尺取法) - 逆风的方向 更适合飞翔 - 博客频道 - CSDN.NET



Description

A sequence of N positive integers (10 < N < 100 000), each of them less than or equal 10000, and a positive integer S (S < 100 000 000) are given. Write a program to find the minimal length of the subsequence of consecutive elements of the sequence, the sum

of which is greater than or equal to S.

Input

The first line is the number of test cases. For each test case the program has to read the numbers N and S, separated by an interval, from the first line. The numbers of the sequence are given in the second line of the test case, separated by intervals. The

input will finish with the end of file.

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[ACM] POJ 3061 Subsequence (尺取法) - 逆风的方向 更适合飞翔 - 博客频道 - CSDN.NET







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