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水中的鱼: [LeetCode] Median of Two Sorted Arrays 解题报告
1: double findMedianSortedArrays(int A[], int m, int B[], int n) {
2: if((n+m)%2 ==0)
3: {
4: return (GetMedian(A,m,B,n, (m+n)/2) + GetMedian(A,m,B,n, (m+n)/2+1))/2.0;
5: }
6: else
7: return GetMedian(A,m,B,n, (m+n)/2+1);
8: }
9: int GetMedian(int a[], int n, int b[], int m, int k)
10: {
11: assert(a && b);
12: if (n <= 0) return b[k-1];
13: if (m <= 0) return a[k-1];
14: if (k <= 1) return min(a[0], b[0]);
15: if (b[m/2] >= a[n/2])
16: {
17: if ((n/2 + 1 + m/2) >= k)
18: return GetMedian(a, n, b, m/2, k);
19: else
20: return GetMedian(a + n/2 + 1, n - (n/2 + 1), b, m, k - (n/2 + 1));
21: }
22: else
23: {
24: if ((m/2 + 1 + n/2) >= k)
25: return GetMedian( a, n/2,b, m, k);
26: else
27: return GetMedian( a, n, b + m/2 + 1, m - (m/2 + 1),k - (m/2 + 1));
28: }
29: }
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1: double findMedianSortedArrays(int A[], int m, int B[], int n) {
2: if((n+m)%2 ==0)
3: {
4: return (GetMedian(A,m,B,n, (m+n)/2) + GetMedian(A,m,B,n, (m+n)/2+1))/2.0;
5: }
6: else
7: return GetMedian(A,m,B,n, (m+n)/2+1);
8: }
9: int GetMedian(int a[], int n, int b[], int m, int k)
10: {
11: assert(a && b);
12: if (n <= 0) return b[k-1];
13: if (m <= 0) return a[k-1];
14: if (k <= 1) return min(a[0], b[0]);
15: if (b[m/2] >= a[n/2])
16: {
17: if ((n/2 + 1 + m/2) >= k)
18: return GetMedian(a, n, b, m/2, k);
19: else
20: return GetMedian(a + n/2 + 1, n - (n/2 + 1), b, m, k - (n/2 + 1));
21: }
22: else
23: {
24: if ((m/2 + 1 + n/2) >= k)
25: return GetMedian( a, n/2,b, m, k);
26: else
27: return GetMedian( a, n, b + m/2 + 1, m - (m/2 + 1),k - (m/2 + 1));
28: }
29: }
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